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Question 144Asked in Bihar STET 2024 Paper II Computer Science, 11 Jun 2024, Shift 2 (3:00 PM)

2/10 + 3/100 + 4/10002/10 + 3/100 + 4/1000

2/10 + 3/100 + 4/1000
  1. A1.2851.285
  2. B0.2340.234
  3. C6.7386.738
  4. D9.2119.211
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Correct answer: (B) 0.2340.234

Explanation

2/10 + 3/100 + 4/1000 = 0.2 + 0.03 + 0.004 = 0.234.2/10 + 3/100 + 4/1000 = 0.2 + 0.03 + 0.004 = 0.234।

From Bihar STET 2024 Paper II Computer Science PYQ, 11 Jun 2024, Shift 2 (3:00 PM)

This is question 144 of Bihar STET 2024 Paper II Computer Science PYQ, 11 Jun 2024, Shift 2 (3:00 PM). See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.