A body of mass 4.9 kg hangs from a spring and oscillates with a period of 0.6 sec. How much will the spring shorten when the body is removed?
Show answerHide answer
Correct answer: (D) 0.089 metre
Explanation
T = 2π√(x/g), so the extension x = gT²/4π² = 9.8 × 0.36 / 39.48 ≈ 0.089 m. The spring shortens by this amount when the mass is removed.