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Question 52

A computer has 128MB memory. Each word in this computer is of 8 bytes. How many bits are required to address any single word in the memory?

  1. A27
  2. B24
  3. C23
  4. D25
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Correct answer: (B) 24

Explanation

128 MB = 2²⁷ bytes. With 8 bytes (2³) per word that is 2²⁷/2³ = 2²⁴ words, so 24 bits are needed.

From DSSSB TGT Computer Science Practice Set 5

This is question 52 of DSSSB TGT Computer Science Practice Set 5. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.