A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and…
A memory management system has 64 pages with 512 bytes page size. Physical memory consists of 32 page frames. Number of bits required in logical and physical address are respectively :
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Correct answer: (C) 15 and 14
Explanation
Logical address space = number of pages × page size = 2⁶ × 2⁹ = 2¹⁵, so the logical address needs 15 bits. Physical address space = number of frames × page size = 2⁵ × 2⁹ = 2¹⁴, so the physical address needs 14 bits.