Question 65Asked in UGC NET Computer Science, June 2016 (Paper II & III, Selected Questions)

Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and…

Assume that we need to download text documents at the rate of 100 pages per minute. A page is an average of 24 lines with 80 characters in each line and each character requires 8 bits. Then the required bit rate of the channel is ...........
  1. A192 mbps
  2. B512 mbps
  3. C1.248 mbps
  4. D1.536 mbps
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Correct answer: (D) 1.536 mbps

Explanation

Note: strictly, 100 pages per minute gives 1,536,000 bits per minute ≈ 25.6 kbps; the keyed 1.536 Mbps corresponds to 100 pages per second, which is how the book solves it. Bits per 100 pages = 100 × 24 × 80 × 8 = 1,536,000 bits ⇒ 1.536 Mbps.

From UGC NET Computer Science PYQ, June 2016 (Paper II & III, Selected Questions)

This is question 65 of UGC NET Computer Science PYQ, June 2016 (Paper II & III, Selected Questions). See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.