Question 107Asked in BPSC TRE 2.0 (2023) Mathematics and Science Class 6-8

Calculate the arithmetic mean from the following frequency distribution :निम्नलिखित बारम्बारता बंटन से समान्तर माध्य की गणना कीजिए :

Calculate the arithmetic mean from the following frequency distribution : Class interval | Frequency 0–10 | 6 10–20 | 10 20–30 | 9 30–40 | 4 40–50 | 11
निम्नलिखित बारम्बारता बंटन से समान्तर माध्य की गणना कीजिए : वर्ग अन्तराल | बारम्बारता 0–10 | 6 10–20 | 10 20–30 | 9 30–40 | 4 40–50 | 11
  1. A2626
  2. B2525
  3. C2424
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (A) 2626

Explanation

Using mid-points 5, 15, 25, 35, 45: Σfx = 30 + 150 + 225 + 140 + 495 = 1040 and Σf = 40, so mean = 26.मध्य-बिन्दु 5, 15, 25, 35, 45 लेने पर Σfx = 30 + 150 + 225 + 140 + 495 = 1040 और Σf = 40, अतः माध्य = 26।

From BPSC TRE 2.0 (2023) Mathematics and Science Class 6-8 — Previous Year Paper

This is question 107 of BPSC TRE 2.0 (2023) Mathematics and Science Class 6-8 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.