Consider the following linear programming problem: Max, z = 0.50x₂ – 0.10x₁
Consider the following linear programming problem:
Max, z = 0.50x₂ – 0.10x₁
Subject to the constraints
2x₁ + 5x₂ ≤ 80
x₁ + x₂ ≤ 20
and x₁, x₂ ≥ 0
The total maximum profit (z) for the above problem is:
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Correct answer: (B) 8
Explanation
z is maximized by taking x₁ = 0 and x₂ as large as possible: 5x₂ ≤ 80 gives x₂ = 16 (and x₁ + x₂ = 16 ≤ 20). So when x₁ = 0 and x₂ = 16, Max z = 0.50 × 16 = 8.