Consider the relation R (PQRSTU) with the set of functional dependencies F = {P → RT, Q → S, R → PS, QS → TU}. Find the closures of PQ.
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Correct answer: (D) PQRSTU
Explanation
PQ⁺: P → RT adds R and T, and Q → S adds S. QS → TU then adds U, so PQ⁺ = PQRSTU (PQ is a key).