Consider the schema R = {S, T, U, V} and the dependencies S → T, T → U, U → V and V → S. If R = (R₁ and R₂) be a decomposition such that R₁ ∩ R₂ = φ then…
Consider the schema R = {S, T, U, V} and the dependencies S → T, T → U, U → V and V → S. If R = (R₁ and R₂) be a decomposition such that R₁ ∩ R₂ = φ then the decomposition is
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Correct answer: (D) In both 2 NF and 3 NF
Explanation
R₁ ∩ R₂ ≠ φ. This makes the decomposition lossless join, as all the attributes are keys, R₁ ∩ R₂ will be a key of the decomposed relation Now, even the original relation R is in 3NF (Even BCNF) as all the attributes are prime attributes (in fact attribute is a candidate key) Hence, any decomposition will also be in 3NF and 2NF, So the answer is option (d).