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Question 21

Determine the size of PROM required for implementing the 16-to-1 multiplexer.

  1. A1M x 1
  2. B2M x 1
  3. C8M x 1
  4. D32M x 1
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Correct answer: (A) 1M x 1

Explanation

A 16-to-1 MUX has 16 data inputs + 4 select lines = 20 inputs. A PROM needs 2²⁰ words × 1 output bit = 1M × 1.

From DSSSB TGT Computer Science Practice Set 2

This is question 21 of DSSSB TGT Computer Science Practice Set 2. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.