For what minimum value of propagation delay in each FF will a 10-bit ripple counter skip a count when it is clocked at 10 MHz?
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Correct answer: (A) 10 ns
Explanation
The ripple counter fails when the total delay of 10 flip-flops reaches the clock period: 10 × t_pd = 1/10 MHz = 100 ns, so t_pd = 10 ns.