Question 28Asked in UGC NET Computer Science, June 2014 (Paper II & III, Selected Questions)

Given U = {1, 2, 3, 4, 5, 6, 7} A = {(3, 0.7), (5, 1), (6, 0.8)}

Given U = {1, 2, 3, 4, 5, 6, 7} A = {(3, 0.7), (5, 1), (6, 0.8)} then ~A will be : (where ~ → complement)
  1. A{(4, 0.7), (2, 1), (1, 0.8)}
  2. B{(4, 0.3), (5, 0), (6, 0.2)}
  3. C{(1, 1), (2, 1), (3, 0.3), (4, 1), (6, 0.2), & (7, 1)}
  4. D{(3, 0.3), (6, 0.2)}
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Correct answer: (C) {(1, 1), (2, 1), (3, 0.3), (4, 1), (6, 0.2), & (7, 1)}

Explanation

Μ~A(x) = 1 − μA(x) for all x ∈ U. The given set A can be seen as A = {(1, 0), (2, 0), (3, 0.7), (4, 0), (5, 1), (6, 0.8), (7, 0)}. So the complement of A is {(1, 1), (2, 1), (3, 0.3), (4, 1), (6, 0.2), (7, 1)} (element 5 has membership 0). Hence the answer is (c).

From UGC NET Computer Science PYQ, June 2014 (Paper II & III, Selected Questions)

This is question 28 of UGC NET Computer Science PYQ, June 2014 (Paper II & III, Selected Questions). See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.