Identify the minimal key for relational scheme R(A, B, C, D, E) with functional dependencies F = {A → B, B → C, AC → D}
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Correct answer: (B) AE
Explanation
{A}⁺ = {A, B, C, D}, which does not include E, so A alone is not a key. {AE}⁺ = {A, B, C, D, E}, and nothing can be removed from AE, so AE is the minimal key.