Question 2Asked in RRB JE CBT-1, 16 Dec 2024, Shift 2 (12:45 PM)

If the radius of a hemisphere is increased by 50%, then find the percentage increase in the volume. (Take π = 22/7)

  1. A112.5%
  2. B150%
  3. C125%
  4. D137.5%
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Correct answer: (C) 125%

Explanation

Official answer key: (3) 125% Correct answer should be 237.5% (not in the options). Volume of a hemisphere = (2/3)πr³, so when r becomes 1.5r the volume becomes 1.5³ = 3.375 times, an increase of 237.5%. 125% is the increase in the curved surface area (1.5² = 2.25 times), not the volume. Scoring follows the official key.

From RRB JE CBT-1 PYQ 16 Dec 2024, Shift 2 (12:45 PM)

This is question 2 of RRB JE CBT-1 PYQ 16 Dec 2024, Shift 2 (12:45 PM). See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.