Question 138Asked in BPSC TRE 2.0 (2023) Language & General Studies Class 1-5

In a certain code TEA = 33 and EAT = 67, then to which one of the following ATE is equal in the same code?यदि एक निश्चित कूट में TEA = 33 एवं EAT = 67 है, तो निम्नलिखित में से ATE उसी कूट में किसके बराबर है?

यदि एक निश्चित कूट में TEA = 33 एवं EAT = 67 है, तो निम्नलिखित में से ATE उसी कूट में किसके बराबर है?
  1. A9090
  2. B8282
  3. C5656
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (C) 5656

Explanation

Let the code be p x first + q x second + r x third value (T=20, E=5, A=1). From TEA = 33 and EAT = 67 we get p = 1, q = 2, r = 3. ATE = 1 x 1 + 2 x 20 + 3 x 5 = 56.कूट को p x पहला + q x दूसरा + r x तीसरा मानें (T=20, E=5, A=1)। TEA = 33 और EAT = 67 से p = 1, q = 2, r = 3 मिलता है। ATE = 1 x 1 + 2 x 20 + 3 x 5 = 56।

From BPSC TRE 2.0 (2023) Language & General Studies Class 1-5 — Previous Year Paper

This is question 138 of BPSC TRE 2.0 (2023) Language & General Studies Class 1-5 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.