Select the 'False' statement from the following statements about Normal forms :
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Correct answer: (C) Any Relation with two attributes is in BCNF
Explanation
Note: statement (c) is actually true (every two-attribute relation is in BCNF); the false statement is (b), so the book's key appears wrong. A BCNF decomposition that is both lossless and dependency preserving is not always possible. Example: R(a, b, c) with FDs ab → c and c → b cannot be decomposed into BCNF while preserving ab → c.