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Question 35Asked in DSSSB PGT Computer Science (Technical), 11 Jul 2021

The binary equivalent of (25.625)₁₀ is ________.

  1. A(10001.11)₂
  2. B(11101.001)₂
  3. C(11011.100)₂
  4. D(11001.101)₂
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Correct answer: (D) (11001.101)₂

Explanation

25 = (11001)₂. For 0.625: ×2 = 1.25 (1), 0.25×2 = 0.5 (0), 0.5×2 = 1.0 (1), giving .101. So 25.625 = (11001.101)₂.

From DSSSB PGT Computer Science PYQ (Technical), 11 Jul 2021

This is question 35 of DSSSB PGT Computer Science PYQ (Technical), 11 Jul 2021. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.