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Question 2Asked in UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)

The hexadecimal equivalent of the octal number 2357 is :

  1. A2EE
  2. B2FF
  3. C4EF
  4. D4FE
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Correct answer: (C) 4EF

Explanation

(2357)₈ = (010 011 101 111)₂. Grouping into 4 bits from right to left: 0100 1110 1111, so it is (4EF)₁₆.

From UGC NET Computer Science PYQ, June 2017 (Paper II & III, Selected Questions)

This is question 2 of UGC NET Computer Science PYQ, June 2017 (Paper II & III, Selected Questions). See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.