Question 1Asked in UGC NET Computer Science, November 2017 (Paper II & III, Selected Questions)

The Octal equivalent of the binary number 1011101011 is :

  1. A7353
  2. B1353
  3. C5651
  4. D5657
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Correct answer: (B) 1353

Explanation

Group the bits in threes from the right: 001 011 101 011. 001 = 1, 011 = 3, 101 = 5, 011 = 3. So (1011101011)₂ = (1353)₈.

From UGC NET Computer Science PYQ, November 2017 (Paper II & III, Selected Questions)

This is question 1 of UGC NET Computer Science PYQ, November 2017 (Paper II & III, Selected Questions). See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.