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Question 118Asked in BPSC TRE 2.0 (2023) Science Class 9-10

The oxidation number of Cr in [Cr(NH₃)₄Cl₂]⁺ is[Cr(NH₃)₄Cl₂]⁺ में Cr की ऑक्सीकरण संख्या है

[Cr(NH₃)₄Cl₂]⁺ में Cr की ऑक्सीकरण संख्या है
  1. A+3+3
  2. B+2+2
  3. C+1+1
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (A) +3+3

Explanation

Ammonia and Cl⁻ contribute 0 and −2 in [Cr(NH₃)₄Cl₂]⁺, so x + 0 − 2 = +1 gives x = +3.[Cr(NH₃)₄Cl₂]⁺ में अमोनिया 0 तथा दो Cl⁻ कुल −2 देते हैं, अतः x + 0 − 2 = +1, x = +3।

From BPSC TRE 2.0 (2023) Science Class 9-10 — Previous Year Paper

This is question 118 of BPSC TRE 2.0 (2023) Science Class 9-10 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.