Question 59Asked in CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026

The value of (√5043 × √50) / (√32 × √1323) is :(√5043 × √50) / (√32 × √1323) का मान है :

(√5043 × √50) / (√32 × √1323) का मान है :
  1. A215/42215/42
  2. B215/84215/84
  3. C205/42205/42
  4. D205/84205/84
Show answerHide answer

Correct answer: (D) 205/84205/84

Explanation

√5043 = 41√3, √50 = 5√2, √32 = 4√2 and √1323 = 21√3. So the value = (41√3 × 5√2)/(4√2 × 21√3) = 205/84.√5043 = 41√3, √50 = 5√2, √32 = 4√2 और √1323 = 21√3। अतः मान = (41√3 × 5√2)/(4√2 × 21√3) = 205/84।

From CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026 — Previous Year Paper

This is question 59 of CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.