Question 43Asked in RRB JE CBT-1, 18 Dec 2024, Shift 1 (9:00 AM)

What is the smallest 4-digit number which, when divided by 12, 16, and 20, gives a remainder of 9?

  1. A1209
  2. B1217
  3. C1017
  4. D1049
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Correct answer: (A) 1209

From RRB JE CBT-1 PYQ 18 Dec 2024, Shift 1 (9:00 AM)

This is question 43 of RRB JE CBT-1 PYQ 18 Dec 2024, Shift 1 (9:00 AM). See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.