What is the value of ∮c e^(2z) / (z + 1)⁴ dz, where c is a circle with centre at origin, |z| = 3?
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Correct answer: (C) (8/3) πi e⁻²
Explanation
The only singularity, z = −1 (a pole of order 4), lies inside |z| = 3. By Cauchy's formula the integral is 2πi·f'''(−1)/3! with f = e^(2z), f''' = 8e^(2z), giving 2πi·8e⁻²/6 = (8/3)πi e⁻².