UTpaper

Free mock tests & test series

Question 63Asked in RRB JE CBT-1, 18 Dec 2024, Shift 3 (4:30 PM)

When 268 is added to 6K8, the result is 9P6. What is the least possible value of K and P for which 9P6 is divisible by 3?

  1. AK=4; P=6
  2. BK=6; P=9
  3. CK=0; P=3
  4. DK=3; P=0
Show answerHide answer

Correct answer: (D) K=3; P=0

From RRB JE CBT-1 PYQ 18 Dec 2024, Shift 3 (4:30 PM)

This is question 63 of RRB JE CBT-1 PYQ 18 Dec 2024, Shift 3 (4:30 PM). See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.