A noiseless channel of bandwidth 3000 Hz uses 2 signal levels. The maximum bit rate (Nyquist) is:
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Correct answer: (D) 6000 bps
Explanation
2 × B × log2(L) = 2 × 3000 × 1 = 6000 bps.
Correct answer: (D) 6000 bps
Explanation
2 × B × log2(L) = 2 × 3000 × 1 = 6000 bps.
This is question 171 of DSSSB TGT Computer Science Full Mock Test 5. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.