Find a unit vector normal to the surface x³ + y³ + 3xyz = 3 at the point (1, 2, -1).

Show answerHide answer
Correct answer: (C)
Explanation
∇f = (3x² + 3yz, 3y² + 3xz, 3xy). At (1, 2, −1) this is (−3, 9, 6) = 3(−1, 3, 2). Its magnitude is 3√14, so the unit normal is (−î + 3ĵ + 2k̂)/√14.



