Question 141Asked in BPSC TRE 2.0 (2023) Mathematics Class 9-10

If (cos²20° + cos²70°) / [2(sin²59° + sin²31°)] = 2/k, then k is equal toयदि (cos²20° + cos²70°) / [2(sin²59° + sin²31°)] = 2/k है, तो k बराबर है

यदि (cos²20° + cos²70°) / [2(sin²59° + sin²31°)] = 2/k है, तो k बराबर है
  1. A33
  2. B11
  3. C44
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
Show answerHide answer

Correct answer: (C) 44

Explanation

cos²70° = sin²20°, so the numerator is 1; sin²59° + sin²31° = 1, so the denominator is 2. Thus 1/2 = 2/k and k = 4.cos²70° = sin²20°, अतः अंश = 1; sin²59° + sin²31° = 1, अतः हर = 2। इस प्रकार 1/2 = 2/k और k = 4।

From BPSC TRE 2.0 (2023) Mathematics Class 9-10 — Previous Year Paper

This is question 141 of BPSC TRE 2.0 (2023) Mathematics Class 9-10 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.