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Question 42Asked in DSSSB TGT Computer Science, 7 Feb 2024, Shift 2 (12:30 PM)

If E1 is 8 times more than E2, then E2 is what percentage less than E1?

  1. A96.96 percent
  2. B88.88 percent
  3. C80.88 percent
  4. D84.88 percent
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Correct answer: (B) 88.88 percent

Explanation

"8 times more" means E1 = E2 + 8E2 = 9E2. E2 is less than E1 by 8E2, i.e. 8/9 × 100 = 88.88 percent.

From DSSSB TGT Computer Science PYQ, 7 Feb 2024, Shift 2 (12:30 PM)

This is question 42 of DSSSB TGT Computer Science PYQ, 7 Feb 2024, Shift 2 (12:30 PM). See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.