Question 47Asked in CTET August 2023 Paper 2 Maths & Science, 20 Aug 2023

If p = (12.34 × 10¹⁰) – (5.67 × 10⁹), then p is expressed in standard form as:यदि p = (12.34 × 10¹⁰) – (5.67 × 10⁹) है, तो p को मानक रूप में निम्न द्वारा व्यक्त किया जाता है :

यदि p = (12.34 × 10¹⁰) – (5.67 × 10⁹) है, तो p को मानक रूप में निम्न द्वारा व्यक्त किया जाता है :
  1. A1.1773 × 10¹¹1.1773 × 10¹¹
  2. B1.1773 × 10¹⁰1.1773 × 10¹⁰
  3. C1.773 × 10¹¹1.773 × 10¹¹
  4. D1.773 × 10¹⁰1.773 × 10¹⁰
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Correct answer: (A) 1.1773 × 10¹¹1.1773 × 10¹¹

Explanation

12.34 × 10¹⁰ = 123.4 × 10⁹, so p = (123.4 – 5.67) × 10⁹ = 117.73 × 10⁹ = 1.1773 × 10¹¹.12.34 × 10¹⁰ = 123.4 × 10⁹, इसलिए p = (123.4 – 5.67) × 10⁹ = 117.73 × 10⁹ = 1.1773 × 10¹¹।

From CTET August 2023 Paper 2 Maths & Science, 20 Aug 2023 — Previous Year Paper

This is question 47 of CTET August 2023 Paper 2 Maths & Science, 20 Aug 2023 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.