Question 56Asked in CTET December 2024 Paper 2 Maths & Science, 14 Dec 2024

If x is the smallest number which is to be subtracted from 2605 to make it a perfect square, then the value of (4x + 7) is :यदि x वह न्यूनतम संख्या है, जिसे 2605 में से घटाने पर वह पूर्ण वर्ग हो जाती है, तो (4x + 7) का मान है :

यदि x वह न्यूनतम संख्या है, जिसे 2605 में से घटाने पर वह पूर्ण वर्ग हो जाती है, तो (4x + 7) का मान है :
  1. A3131
  2. B1111
  3. C2323
  4. D2727
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Correct answer: (C) 2323

Explanation

51² = 2601 and 52² = 2704, so x = 2605 − 2601 = 4 and 4x + 7 = 23.51² = 2601 और 52² = 2704, इसलिए x = 2605 − 2601 = 4 और 4x + 7 = 23।

From CTET December 2024 Paper 2 Maths & Science, 14 Dec 2024 — Previous Year Paper

This is question 56 of CTET December 2024 Paper 2 Maths & Science, 14 Dec 2024 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.