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Question 136Asked in BPSC TRE 2.0 (2023) Computer Science Class 11-12

If (X567)₈ + (2YX5)₈ = (71YX)₈, then the values of X and Y are

  1. A4, 3
  2. B3, 3
  3. C4, 4
  4. DMore than one of the above
  5. ENone of the above
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Correct answer: (A) 4, 3

Explanation

Take X=4, Y=3 and add 4567 + 2345 in octal. 7+5 = 12 = 4 carry 1, 6+4+1 = 3 carry 1, 5+3+1 = 1 carry 1, 4+2+1 = 7. The sum is 7134 = (71YX)₈.

From BPSC TRE 2.0 (2023) Computer Science Class 11-12 — Previous Year Paper

This is question 136 of BPSC TRE 2.0 (2023) Computer Science Class 11-12 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.