Question 35Asked in BPSC TRE 2.0 (2023) English Class 6-8 + 2 more papers

In a △ABC, if AB = 16 cm, BC = 12 cm and AC = 20 cm, then △ABC is△ABC में, यदि AB = 16 से.मी., BC = 12 से.मी. और AC = 20 से.मी. हैं, तो △ABC है

△ABC में, यदि AB = 16 से.मी., BC = 12 से.मी. और AC = 20 से.मी. हैं, तो △ABC है
  1. Aacute-angledन्यूनकोण
  2. Bright-angledसमकोण
  3. Cobtuse-angledअधिककोण
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (B) right-angledसमकोण

Explanation

16^2 + 12^2 = 256 + 144 = 400 = 20^2, so the triangle is right-angled.16^2 + 12^2 = 400 = 20^2, इसलिए त्रिभुज समकोण है।

From BPSC TRE 2.0 (2023) English Class 6-8 — Previous Year Paper

This is question 35 of BPSC TRE 2.0 (2023) English Class 6-8 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.

Asked in 3 papers