Match the following : List–I
Match the following :
List–I
(a) (p→q) ⇔ (¬q→¬p)
(b) [(p∧q)→r] ⇔ [p→(q→r)]
(c) (p→q) ⇔ [(p∧¬q)→0]
(d) (p↔q) ⇔ [(p→q) ∧ (q→p)]
List–II
(i) Contrapositive
(ii) Exportation law
(iii) Reductio ad absurdum
(iv) Equivalence
Codes : a b c d
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Correct answer: (A) (i) (ii) (iii) (iv)
Explanation
(a) Contrapositive: negate both hypothesis and conclusion and interchange them: (p → q) ⇔ (¬q → ¬p). (b) Exportation is a valid rule of replacement: ((p ∧ q) → r) ⇔ (p → (q → r)). (c) Reductio ad absurdum: (p → q) ⇔ [(p ∧ ¬q) → 0]. (d) Equivalence (biconditional): (p ↔ q) ⇔ (p → q) ∧ (q → p). So a-(i), b-(ii), c-(iii), d-(iv).