Question 51Asked in CTET December 2024 Paper 2 Maths & Science, 14 Dec 2024

One of the factors of 20pq² + 4pq + 45pr² − 60pqr − 6rp is :20pq² + 4pq + 45pr² − 60pqr − 6rp के गुणनखंडों में से एक गुणनखंड निम्न है :

20pq² + 4pq + 45pr² − 60pqr − 6rp के गुणनखंडों में से एक गुणनखंड निम्न है :
  1. A15p − 10r + 215p − 10r + 2
  2. B2r − 3q2r − 3q
  3. C2q − 3r2q − 3r
  4. D10p − 15r + 210p − 15r + 2
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Correct answer: (C) 2q − 3r2q − 3r

Explanation

20pq² − 60pqr + 45pr² + 4pq − 6pr = 5p(2q − 3r)² + 2p(2q − 3r) = p(2q − 3r)(10q − 15r + 2). So 2q − 3r is a factor.20pq² − 60pqr + 45pr² + 4pq − 6pr = 5p(2q − 3r)² + 2p(2q − 3r) = p(2q − 3r)(10q − 15r + 2)। अतः 2q − 3r एक गुणनखंड है।

From CTET December 2024 Paper 2 Maths & Science, 14 Dec 2024 — Previous Year Paper

This is question 51 of CTET December 2024 Paper 2 Maths & Science, 14 Dec 2024 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.