Question 49Asked in CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026

One of the factors of 4x² + 9y² + 12xy − 5(2x + 3y) − 14 is :4x²+9y²+12xy−5(2x+3y)−14 का एक गुणनखंड है :

4x²+9y²+12xy−5(2x+3y)−14 का एक गुणनखंड है :
  1. A2x + 3y − 72x+3y−7
  2. B2x + 3y + 72x+3y+7
  3. C2x + 3y + 142x+3y+14
  4. D2x + 3y − 22x+3y−2
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Correct answer: (A) 2x + 3y − 72x+3y−7

Explanation

Put t = 2x + 3y: the expression is t² − 5t − 14 = (t − 7)(t + 2). So 2x + 3y − 7 is a factor.माना t = 2x + 3y: व्यंजक t² − 5t − 14 = (t − 7)(t + 2) है। अतः 2x + 3y − 7 एक गुणनखंड है।

From CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026 — Previous Year Paper

This is question 49 of CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.