Question 48Asked in CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026

The following observations have been written in the ascending order :निम्न प्रेक्षण आरोही क्रम में लिखें हुए हैं :

The following observations have been written in the ascending order : 28, 31, 47, 51, a, a+3, 71, 74, 78, 90 If the median of the data is 61.5, then the mean of the data is :
निम्न प्रेक्षण आरोही क्रम में लिखें हुए हैं : 28, 31, 47, 51, a, a+3, 71, 74, 78, 90 यदि इन आंकड़ों का माध्यक 61.5 है, तो इन आंकड़ों का माध्य है :
  1. A59.259.2
  2. B59.359.3
  3. C58.158.1
  4. D58.458.4
Show answerHide answer

Correct answer: (B) 59.359.3

Explanation

Median = (a + a + 3)/2 = 61.5 gives a = 60. Sum = 28 + 31 + 47 + 51 + 60 + 63 + 71 + 74 + 78 + 90 = 593, so mean = 593/10 = 59.3.माध्यक = (a + a + 3)/2 = 61.5 से a = 60। योग = 28 + 31 + 47 + 51 + 60 + 63 + 71 + 74 + 78 + 90 = 593, अतः माध्य = 593/10 = 59.3।

From CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026 — Previous Year Paper

This is question 48 of CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.