Question 36Asked in CTET December 2024 Paper 2 Maths & Science, 15 Dec 2024

One of the factors of 81x² − 126xy + 49y² − (5x + 3y)² is81x² − 126xy + 49y² − (5x + 3y)² के गुणनखंडों में से एक गुणनखंड है

81x² − 126xy + 49y² − (5x + 3y)² के गुणनखंडों में से एक गुणनखंड है
  1. A7x + 2y7x + 2y
  2. B2x + 5y2x + 5y
  3. C7x − 2y7x − 2y
  4. D5x − 7y5x − 7y
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Correct answer: (C) 7x − 2y7x − 2y

Explanation

81x² − 126xy + 49y² = (9x − 7y)². So the expression is (9x − 7y)² − (5x + 3y)² = (4x − 10y)(14x − 4y) = 4(2x − 5y)(7x − 2y). Hence 7x − 2y is a factor.81x² − 126xy + 49y² = (9x − 7y)² है। अतः व्यंजक (9x − 7y)² − (5x + 3y)² = (4x − 10y)(14x − 4y) = 4(2x − 5y)(7x − 2y) है। इसलिए 7x − 2y एक गुणनखंड है।

From CTET December 2024 Paper 2 Maths & Science, 15 Dec 2024 — Previous Year Paper

This is question 36 of CTET December 2024 Paper 2 Maths & Science, 15 Dec 2024 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.