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Question 116

Round Robin with quantum 4: P1 = 10 and P2 = 4, both arriving at time 0 (P1 first). The average waiting time is:

  1. A6
  2. B5
  3. C7
  4. D4
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Correct answer: (D) 4

Explanation

P1(0–4) P2(4–8) P1(8–14). WT: P1 = 14 − 10 = 4, P2 = 4. Average 4.

From DSSSB TGT Computer Science Full Mock Test 5

This is question 116 of DSSSB TGT Computer Science Full Mock Test 5. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.