Question 109Asked in BPSC TRE 2.0 (2023) Mathematics and Science Class 6-8

Simplify : (sin θ + sin 3θ + sin 5θ) / (cos θ + cos 3θ + cos 5θ)सरल कीजिए :

Simplify : (sin θ + sin 3θ + sin 5θ) / (cos θ + cos 3θ + cos 5θ)
सरल कीजिए : (sin θ + sin 3θ + sin 5θ) / (cos θ + cos 3θ + cos 5θ)
  1. Acot 3θcot 3θ
  2. Btan 3θtan 3θ
  3. Ctan 2θtan 2θ
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (B) tan 3θtan 3θ

Explanation

sin θ + sin 5θ = 2 sin 3θ cos 2θ, so the numerator is sin 3θ(2cos 2θ + 1); likewise the denominator is cos 3θ(2cos 2θ + 1). The ratio is tan 3θ.sin θ + sin 5θ = 2 sin 3θ cos 2θ, अतः अंश = sin 3θ(2cos 2θ + 1); इसी प्रकार हर = cos 3θ(2cos 2θ + 1)। अनुपात tan 3θ है।

From BPSC TRE 2.0 (2023) Mathematics and Science Class 6-8 — Previous Year Paper

This is question 109 of BPSC TRE 2.0 (2023) Mathematics and Science Class 6-8 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.