Suppose that a biased coin is tossed such that P(H) = 2/3 and P(T) = 1/3.
Suppose that a biased coin is tossed such that P(H) = 2/3 and P(T) = 1/3.
If head (H) appears, a number between is selected between 1 through 9. If tail (T)
appears, then a number is selected between 1 through 5. The probability that an even
number is selected is approximately equal to:
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Correct answer: (D) 0.43
Explanation
P(even) = P(H) x 4/9 + P(T) x 2/5 = (2/3)(4/9) + (1/3)(2/5) = 8/27 + 2/15 ≈ 0.296 + 0.133 = 0.43.