Question 31Asked in CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026

The greatest number that divides 87 and 123 leaving respectively 7 and 3 as remainders is :वह सबसे बड़ी संख्या, जिससे 87 और 123 को भाग देने पर क्रमशः 7 और 3 शेष बचे, है :

वह सबसे बड़ी संख्या, जिससे 87 और 123 को भाग देने पर क्रमशः 7 और 3 शेष बचे, है :
  1. A2020
  2. B3636
  3. C4040
  4. D8080
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Correct answer: (C) 4040

Explanation

The number must divide 87 − 7 = 80 and 123 − 3 = 120 exactly, so it is HCF(80, 120) = 40 (and 40 is greater than both remainders).संख्या को 87 − 7 = 80 और 123 − 3 = 120 को पूर्णतः विभाजित करना होगा, इसलिए यह HCF(80, 120) = 40 है (और 40 दोनों शेषफलों से बड़ा है)।

From CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026 — Previous Year Paper

This is question 31 of CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.