Question 46Asked in CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026

The perimeter and area of a trapezium are respectively 52 cm and 128 cm². If the sum of its non-parallel sides is 20 cm, then the distance between its…किसी समलंब के परिमाप और क्षेत्रफल क्रमशः 52 cm और 128 cm² हैं। यदि इसकी असमांतर भुजाओं का योग 20 cm है, तो इसकी समांतर भुजाओं के बीच की दूरी है :

The perimeter and area of a trapezium are respectively 52 cm and 128 cm². If the sum of its non-parallel sides is 20 cm, then the distance between its parallel sides is :
किसी समलंब के परिमाप और क्षेत्रफल क्रमशः 52 cm और 128 cm² हैं। यदि इसकी असमांतर भुजाओं का योग 20 cm है, तो इसकी समांतर भुजाओं के बीच की दूरी है :
  1. A6 cm6 cm
  2. B8 cm8 cm
  3. C10 cm10 cm
  4. D12 cm12 cm
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Correct answer: (B) 8 cm8 cm

Explanation

Sum of parallel sides = 52 − 20 = 32 cm. Area = ½ × 32 × h = 128, so h = 8 cm.समांतर भुजाओं का योग = 52 − 20 = 32 सेमी। क्षेत्रफल = ½ × 32 × h = 128, इसलिए h = 8 सेमी।

From CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026 — Previous Year Paper

This is question 46 of CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.