Question 56Asked in CTET February 2026 Paper 1, 8 Feb 2026

The perimeter of a rectangle is 410 m and its length is 123 m. The breadth of the rectangle (in m) is:एक आयत का परिमाप 410 m है और इसकी लंबाई 123 m है। आयत की चौड़ाई (m में) है :

एक आयत का परिमाप 410 m है और इसकी लंबाई 123 m है। आयत की चौड़ाई (m में) है :
  1. A8282
  2. B8686
  3. C8888
  4. D9292
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Correct answer: (A) 8282

Explanation

Perimeter = 2(l + b), so l + b = 410 ÷ 2 = 205 m and b = 205 − 123 = 82 m.परिमाप = 2(l + b), इसलिए l + b = 410 ÷ 2 = 205 m और b = 205 − 123 = 82 m।

From CTET February 2026 Paper 1, 8 Feb 2026 — Previous Year Paper

This is question 56 of CTET February 2026 Paper 1, 8 Feb 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.