Question 57Asked in CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026

The perimeters of two circular fields C1 and C2 are 40π m and 96π m, respectively. What is the radius of the third circular field C3 whose area is equal to…दो वृत्ताकार खेतों C1 और C2 के परिमाप क्रमशः 40 π m तथा 96 π m हैं। तीसरे खेत C3 की त्रिज्या क्या होगी, यदि इसका क्षेत्रफल C1 और C2 के क्षेत्रफलों के योग के…

The perimeters of two circular fields C1 and C2 are 40π m and 96π m, respectively. What is the radius of the third circular field C3 whose area is equal to the sum of the areas of C1 and C2 ?
दो वृत्ताकार खेतों C1 और C2 के परिमाप क्रमशः 40 π m तथा 96 π m हैं। तीसरे खेत C3 की त्रिज्या क्या होगी, यदि इसका क्षेत्रफल C1 और C2 के क्षेत्रफलों के योग के बराबर है?
  1. A52 m52 m
  2. B53 m53 m
  3. C68 m68 m
  4. D51 m51 m
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Correct answer: (A) 52 m52 m

Explanation

2πr = 40π gives r1 = 20 m; 2πr = 96π gives r2 = 48 m. r3² = 20² + 48² = 400 + 2304 = 2704, so r3 = 52 m.2πr = 40π से r1 = 20 m; 2πr = 96π से r2 = 48 m। r3² = 20² + 48² = 400 + 2304 = 2704, अतः r3 = 52 m।

From CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026 — Previous Year Paper

This is question 57 of CTET February 2026 Paper 2 Maths & Science, 8 Feb 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.