Question 78Asked in BPSC TRE 3.0 (2024) Physics Class 11-12

What should be the velocity of a person of weight 60 kg, so that his kinetic energy becomes 270 J?60 किलोग्राम वजन वाले व्यक्ति का वेग कितना होना चाहिए, ताकि उसकी गतिज ऊर्जा 270 J हो जाए?

60 किलोग्राम वजन वाले व्यक्ति का वेग कितना होना चाहिए, ताकि उसकी गतिज ऊर्जा 270 J हो जाए?
  1. A10 m s⁻¹10 m s⁻¹
  2. B20 m s⁻¹20 m s⁻¹
  3. C3 m s⁻¹3 m s⁻¹
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (C) 3 m s⁻¹3 m s⁻¹

Explanation

KE = ½mv², so v² = 2 × 270/60 = 9 and v = 3 m s⁻¹.KE = ½mv², अतः v² = 2 × 270/60 = 9 और v = 3 m s⁻¹।

From BPSC TRE 3.0 (2024) Physics Class 11-12 — Previous Year Paper

This is question 78 of BPSC TRE 3.0 (2024) Physics Class 11-12 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.