Question 96Asked in BPSC TRE 2.0 (2023) Mathematics and Science Class 6-8

When (x³ − 10x² + 2x + 3) is divided by (x + 1), the remainder is(x³ − 10x² + 2x + 3) को (x + 1) से विभाजित करने पर शेषफल मिलता है

(x³ − 10x² + 2x + 3) को (x + 1) से विभाजित करने पर शेषफल मिलता है
  1. A–1–1
  2. B–10–10
  3. C22
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
Show answerHide answer

Correct answer: (B) –10–10

Explanation

By the remainder theorem put x = -1: -1 - 10 - 2 + 3 = -10.शेषफल प्रमेय से x = -1 रखने पर: -1 - 10 - 2 + 3 = -10।

From BPSC TRE 2.0 (2023) Mathematics and Science Class 6-8 — Previous Year Paper

This is question 96 of BPSC TRE 2.0 (2023) Mathematics and Science Class 6-8 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.