Question 75Asked in BPSC TRE 3.0 (2024) Mathematics Class 9-10a³ – b³ is equal toa³ – b³ बराबर है
a³ – b³ बराबर है
- A(a – b)³ – 3ab(a – b)(a – b)³ – 3ab(a – b)
- B(a – b)³ + 3ab(a – b)(a – b)³ + 3ab(a – b)
- C(a + b)³ – 3ab(a + b)(a + b)³ – 3ab(a + b)
- DMore than one of the aboveउपर्युक्त में से एक से अधिक
- ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (B) (a – b)³ + 3ab(a – b)(a – b)³ + 3ab(a – b)
Explanation
(a − b)³ = a³ − b³ − 3ab(a − b), so a³ − b³ = (a − b)³ + 3ab(a − b).(a − b)³ = a³ − b³ − 3ab(a − b), अतः a³ − b³ = (a − b)³ + 3ab(a − b)।