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Question 116

FCFS scheduling: P1 (arrival 0, burst 4), P2 (arrival 1, burst 3), P3 (arrival 2, burst 1).

FCFS scheduling: P1 (arrival 0, burst 4), P2 (arrival 1, burst 3), P3 (arrival 2, burst 1). Average turnaround time is:
  1. A4
  2. B6
  3. C4.67
  4. D5.33
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Correct answer: (D) 5.33

Explanation

Completion 4, 7, 8 → TAT 4, 6, 6 → 16/3 ≈ 5.33.

From DSSSB TGT Computer Science Full Mock Test 3

This is question 116 of DSSSB TGT Computer Science Full Mock Test 3. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.