Question 33Asked in CTET February 2026 Paper 1, 1 Mar 2026

If 1001 × 121 = 11 × 12111 – 275 × ___________, then what is the number at the blank space?यदि 1001 × 121 = 11 × 12111 – 275 × ___________ है, तो रिक्त स्थान पर कौन-सी संख्या होगी ?

यदि 1001 × 121 = 11 × 12111 – 275 × ___________ है, तो रिक्त स्थान पर कौन-सी संख्या होगी ?
  1. A4242
  2. B8888
  3. C4444
  4. D2222
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Correct answer: (C) 4444

Explanation

1001 × 121 = 121121 and 11 × 12111 = 133221. The difference is 133221 − 121121 = 12100, and 12100 ÷ 275 = 44.1001 × 121 = 121121 और 11 × 12111 = 133221। अंतर 133221 − 121121 = 12100 है, और 12100 ÷ 275 = 44।

From CTET February 2026 Paper 1, 1 Mar 2026 — Previous Year Paper

This is question 33 of CTET February 2026 Paper 1, 1 Mar 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.