Question 37Asked in CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026

If (7x − 1)/4 − (1/3)(2x − (1 − x)/2) = 10/3, then what is the value of (11x + 21)/2?यदि (7x − 1)/4 − (1/3)(2x − (1 − x)/2) = 10/3 है, तो (11x + 21)/2 का मान क्या है?

यदि (7x − 1)/4 − (1/3)(2x − (1 − x)/2) = 10/3 है, तो (11x + 21)/2 का मान क्या है?
  1. A2727
  2. B2929
  3. C3131
  4. D3232
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Correct answer: (C) 3131

Explanation

2x − (1 − x)/2 = (5x − 1)/2, so the equation is (7x − 1)/4 − (5x − 1)/6 = 10/3. Multiplying by 12: 21x − 3 − 10x + 2 = 40, so 11x = 41. Then (11x + 21)/2 = (41 + 21)/2 = 31.2x − (1 − x)/2 = (5x − 1)/2, इसलिए समीकरण (7x − 1)/4 − (5x − 1)/6 = 10/3 है। 12 से गुणा करने पर: 21x − 3 − 10x + 2 = 40, इसलिए 11x = 41। तब (11x + 21)/2 = (41 + 21)/2 = 31।

From CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026 — Previous Year Paper

This is question 37 of CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.